#include< stdio.h>
#include< stdlib.h>
int main()
{
	int *a,n,i,j,temp;
	printf("Enter size of array:");
	scanf("%d",&n);

	a = malloc(sizeof(int)*n);

	printf("Enter %d Elements:",n);
	for(i=0;i< n;i++)
	{
		scanf("%d",&a[i]);
	}

	for(i=0;i< n-1;i++)
	{
		for(j=0;j< n-1;j++)
		{
			if(a[j]>a[j+1])
			{
				temp=a[j];
				a[j]=a[j+1];
				a[j+1]=temp;
			}
		}
	}
	printf("After sorting it in ascending order:");
	for(i=0;i< n;i++)
	{
		printf("%d ",a[i]);
	}
	getch();
				
}

Program Explanation

Step 1 : Include header files (#include< stdio.h> and #include< conio.h>).

Step 2 : Start with main function with return type.

Step 3 : parenthesis to start and end the program { }.

Step 4 : declare variables with data type i.e, '*a,n,i,j,temp' is an integer type so we use "int" data type.

Step 5 : Use output function printf() to print the output on the screen.

Step 6 : Use input function scanf() to get input from the user.

Step 7 : here, Sort the Elements in ascending order an array ,Enter size of array . then scanf function was seen this size of array , and give a message on screen enter a element after enter element, then loop will start and check the condition.then condition was true the enter the loop and scanf function was seen the a[i] and then go to another loop for(i=0;i< n-1;i++) and check condition and then go to loop for(j=0;j< n-1;j++) here also condition was it will check if statement ,if(a[j]>a[j+1]) and then inter the loop and calculated the expression and print the "After sorting it in ascending order" and then for loop was run for(i=0;i< n;i++) and give output of the program "a[i]" :

Step 8 : using getch() function to hold the screen.